-5x^2-106x-561=0

Solution for -5x^2-106x-561=0 equation:

-5x^2-106x-561=0

a = -5; b = -106; c = -561;
Δ = b2-4ac
Δ = -1062-4·(-5)·(-561)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-106)-4}{2*-5}=\frac{102}{-10}
=-10+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-106)+4}{2*-5}=\frac{110}{-10}
=-11
$